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I had to experiment spinning a spinner [48 times] and collect the data.
10:00= 19 times
11:00= 17 times
12:00= 12 times.
The question is: "If Kalvin uses this spinner for 90 days long to determine his bedtime, how many nights do you think he will go to bed at 10:00? At 11:00? At 12:00?" How do I calculate the problem?

2007-03-03 16:45:11 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

It came up 10:00 about 39.6% of the time so he would go to bed at 10:00 about 35.64 days out of 90. round to 36 days

It came up 11:00 about 35.4% of the time so he would go to bed at 11:00 about 31.86 days out of 90. round to 32 days

It came up 12:00 25% of the time so he would go to bed at 12:00 about 22.5 days out of 90. round to 23 days

You may want to round one of those down so that the total days add up to 90 days and not 91.

2007-03-03 17:03:02 · answer #1 · answered by PZ 4 · 1 0

I don't really know what a spinner is, but given your data, the probability of

10:00 is 19/48 or ~40%
11:00 is 17/48 or ~35%
12:00 is 12/48 or ~25%

so, multiply the fraction by 90 for each you get

35.625 nights (~40% of the 90 days) Kalvin goes to bed at 10:00
31.875 nights (~35% of the 90 days) Kalvin goes to bed at 11:00
22.500 nights (~25% of the 90 days) Kalvin goes to bed at 12:00

2007-03-04 01:03:49 · answer #2 · answered by fifty2weekhi 2 · 1 0

(19/48)*90 = 35.625 times at 10:00
(17/48)*90 = 31.875 times at 11:00
(12/48)* 90 = 22.5 times at 12:00

So round the numbers to get
10:00 36 times
11:00 32 times
12:00 22 times

2007-03-04 01:06:29 · answer #3 · answered by ironduke8159 7 · 1 0

Simple ratios will do for this one:
10:00 ==> 19*90/48
10:00 ==> 17*90/48
10:00 ==> 12*90/48

2007-03-04 00:57:07 · answer #4 · answered by Helmut 7 · 1 0

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