Can someone help with a caculus problem?

Question

f(x)=9x-x²

Can someone please give the steps in detail, so that I can understand how to do it?

Answer 1

well if you are taking a derivative it would help if you had said something about it, but here goes. for a derivative you take the exponent and multiply the coefficient by that number then subtract one from the exponent.

one should wind up with 9-2x

Answer 2

Ok if your are looking for the derivative, your answer would be f'(x)=9-2x

The derivative of 9x is 9. This happens because the derivative of x=1 and since it is multiplied by 9 you just multiply both numbers.

The derivative of x² is 2x. Just multiply x by the original exponent (2). Then change the exponent by substracting 1. (2-1=1)

Answer 3

Yours is not an easy problem to solve!

The function when x=0 is 0: f(0) =9*0 - (0)^2 = 0

The function's first derivative, with respect to x, is 9 - 2x: f'(x) = 9 - 2x.

The function's second derivative, with respect to x, is -2: f"(x) = -2.

That the 2nd derivative is neg implies that critical value(s) for the first derivative cause a maximum for the function.

[If you provided more detail about what you're wondering about, it might be easier to get/give an answer.]

Answer 4

if u want to differentitate then:
f'(x)=9-2x
if u want to integrate:
integrate 9x-x^2 d(x)
=9x^2/2 - x^3/3 +C

Answer 5

they dont use that ina ny work place,
that is why it is the sam eword as calculater,

that is what schools are trying to peddel or ale.

havent you ever heard of coming up with something, and waiting for someone to find away, to put it to use