Each of the coil springs of a car has a spring constant of 25,000 N/m. How much is each spring compressed if it supports one-fourth of the car's 12,000-N weight?
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2007-03-03 15:16:11 · 4 answers · asked by swimmertommy 1 in Science & Mathematics ➔ Physics
The force exterted by a spring is F in N
The spring rate is K(N/m).
The displacement of a spring is represented by x.
F=Kx
If 1 spring support 3,000 N, the displacement or compression of the spring is
x=F/K or
x=3,000/25,000N/m=0..12m
2007-03-03 15:25:07 · answer #1 · answered by SWH 6 · 2⤊ 0⤋
Ok this isnt too bad. Assume weight is evenly distributed. Each spring applies a 3000N force.
Force of spring = kx.
3,000 N = (25,000 N/m)(x meters)
x = 3/25 meters
2007-03-03 15:21:52 · answer #2 · answered by thereytrain 2 · 0⤊ 0⤋
X (m) * 25,000 (N/m) = 1/4 * 12,000 N
X=0.12 m =12 cm
2007-03-03 15:21:29 · answer #3 · answered by TfC_137 3 · 0⤊ 0⤋
force on each wheel=12000/4=300
compression=F/k=300/25000=0.012m
2007-03-03 15:21:46 · answer #4 · answered by llcold 2 · 0⤊ 1⤋