real number?

3 ⤊

solve w^2 = 4 where w is a real number

Simplify your answer as much as possible

If there is more than one solution than write them all

2007-03-03 14:49:28 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

w^2 = 4

Move the 4 to the left hand side.

w^2 - 4 = 0

Factor.

(w - 2)(w + 2) = 0

Therefore, w = 2, -2

2007-03-03 15:06:23 · answer #1 · answered by Puggy 7 · 1⤊ 0⤋

w^2 = 4 then w^2-4=0 so (w-2)(w+2)-0 or w=2 or w=-2.

2007-03-04 01:38:44 · answer #2 · answered by Ahmad k 2 · 0⤊ 0⤋

Take the square root of both sides. sqrt4 = +-w, w = 2, -2

2007-03-03 22:54:23 · answer #3 · answered by Lump 1 · 1⤊ 0⤋

w^2 = 4
w = root of 4
w = 2 (final answer)

2007-03-03 23:09:10 · answer #4 · answered by dchosen1_007 2 · 1⤊ 1⤋