2007-03-03 14:47:16 · 5 answers · asked by arbpdx1 1 in Science & Mathematics ➔ Mathematics
Sorry yes 2 is the base.
2007-03-03 14:54:53 · update #1
I'm not sure if the - is supposed to be a "dash" or a negative. I'm going to assume that it's a dash.
log[base 2](32)
Let x = log[base 2](32).
To solve this, convert this to exponential form.
2^x = 32
Now, use the fact that 32 is a power of 2; in fact, it's 2 to the power of 5.
2^x = 2^5
Same base, different exponent. Equate the exponents.
x = 5
2007-03-03 14:52:44 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
If you mean log base 32 of 2, it's asking 32 ^ ? = 2, which would be 1/5, because 2 is the 5th root of 32.
2007-03-03 14:53:34 · answer #2 · answered by Lump 1 · 0⤊ 0⤋
2 to what power is 32?
2^5 = 32
2007-03-03 14:53:03 · answer #3 · answered by David S 4 · 0⤊ 0⤋
log (Base 2) 32
2^x = 32
= 2^5
Therefore, x = 5
2^x = 2^5
2007-03-03 15:02:41 · answer #4 · answered by Anonymous · 0⤊ 0⤋
log [base 2] of 32
2^x=32
x log 2 = log 32
divide by log 2
x=5
2007-03-03 15:56:41 · answer #5 · answered by abcde12345 4 · 0⤊ 0⤋