A woman of mass 55kg jumps off the bow of a 75kg canoe that is initially at rest. If her verlocity is 2.5m/s to the right, what is the velocity of the canoe after she jumps?
2007-03-03 14:45:22 · 4 answers · asked by cute b 1 in Science & Mathematics ➔ Physics
Momentum is conserved, so m1v1 = m2v2 in the opposite direction. If m1 is the canoe, 75 * v1 = 55 * 2.5 = 137.5, so v1 = 137.5 / 75 = 1.833 or 1.8 m/s to the left.
2007-03-03 14:53:46 · answer #1 · answered by hznfrst 6 · 0⤊ 0⤋
m=mass of woman=55kg
M=mass of canoe=75kg
v=velocity of woman=2.5m/s
V=?
mv=MV
55*2.5=75*V
V=1.833m/s
2007-03-04 00:15:54 · answer #2 · answered by shohag 1 · 0⤊ 0⤋
55 x 2.5 = 75 x V; solve for V.
2007-03-03 22:55:01 · answer #3 · answered by Anonymous · 0⤊ 0⤋
mass of woman X her velo = mass of canoe X velo of canoe
55 X 5.2 = 75 X velo of canoe
Canoe velo = 55x5.2/75
2007-03-03 22:54:00 · answer #4 · answered by cookiedada 3 · 0⤊ 0⤋