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(root 6 + 4* root 3 +3 * root 2)/ ( ( root 6+ root 3)(root 3+root 2) )
=[root6+4root3+3root2]/[root18+root12+root9 + root6]
=[root6+4root3+3root2]/[3root2+2root3+3+ root6]
=[6 + 4root18+3root12]/[3root12 +2root 18 +3+6]
= [6 +12 root 3 +6root2]/[6root3 +6 root 2 +9]
=[1+ 2root3+root2]/[root3+ root2 +1.5]

2007-03-03 15:24:15 · answer #1 · answered by ironduke8159 7 · 0 0

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