Parabola problems help?

Question

y = (x - 3)^2 - 5

Graph the parabola, plot the vertesx and four additional points, two on each side of the vertex.

What would the points be?

Answer 1

y = (x - 3)^2 - 5

y= x^2 -6x+9 - 5
y = x^2 -6x +4
Axis of symmetry is -b/2a = -(-6)/2*1 = 3
vertex is at (3,f(3)) = (3, -5)
When x = 0 rr 6 y = 4, so (0,4) and (6,4) are two points
When x = 2 or 4 y = -4 so (2,-4) and (4,-4) are two more points

Answer 2

Vertex (3, -5)

Pick 2 and 4 for x, y = -4

Pick 1 and 5 for x, y = -1