Can anyone solve this Algebra problem?

Question

4(5n-7) = 10n+2

Could you please explain it step-by-step? Thank you

Answer 1

4(5n-7) = 10n+2
now you expand the left side of the equation

20n-28 = 10n+2
now you get the variables on one side and the numbers on the other.

20n-10n = 2+28
10n = 30
divide through by 10 to get 'n' by itself

n=3

Answer 2

4*(+5n) + 4*(-7) = 10n + 2

20n - 28 = 10n + 2

20n - 10n = 2 + 28

10n = 30

10n/10 = 30/10 (divide both sides of equation by 10)

n = 3

Answer 3

4(5n-7) = 10n + 2

Multiply parens:

20n - 28 = 10n + 2

then balance

20n = 10n + 30 (when you move a neg number to balance it's postive on the other side so, +2 +28 = 30

same action for the n

10n = 30 (got this by : 20n - 10n = 10n)

Solve for n

n=3 (divide 30 by 10)

Best I can do, algebra was long long ago for me.

Answer 4

4(5n - 7) = 10n + 2

First, expand the left hand side.

4(5n) - 4(7) = 10n + 2

Simplify the left hand side.

20n - 28 = 10n + 2

Now, move everything with an n to the left hand side; everything else goes to the right hand side.

20n - 10n = 28 + 2
10n = 30
n = 3

Answer 5

4(5n-7) = 10n+2
20n-28=10n+2
20n-10n-28+28 = 10n-10n+2+28
10n=30
10n/10=30/10
n=3

Answer 6

first distribute for the left side so

20n-28=10n+2

Then combine like terms

20n-10n=28+2

10n=30

n=3

Answer 7

20n-28=10n+2
20n-28+28=10n+2+28
20n=10n+30
20n-10n=10n-10n+30
10n=30
n=3