on a number line graph the solution to the quadratic inequality
-x^2 - 8x (greater than or equal to) 16
If there is no real solution than say so
2007-03-03 13:09:29 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
-x^2 - 8x >= 16
0 >= x^2 + 8x + 16
0 >= (x+4)^2
so the only real solution for x is -4. otherwise, (x+4)^2 is greater than 0.
2007-03-03 13:48:27 · answer #1 · answered by iluxa 5 · 0⤊ 0⤋
-x^2 - 8x >= 16 (add x^2 + 8x to both sides)
0 >= x^2 + 8x + 16 (factorise)
0 >= (x + 4) (x + 4) (therefore...)
x <= -4
P.S. It is fun.
2007-03-03 13:17:17 · answer #2 · answered by alan_mesfin 2 · 0⤊ 1⤋
I don't think that's fun, then again that's why I majored in history/english
2007-03-03 13:12:13 · answer #3 · answered by Anonymous · 0⤊ 1⤋
This question isn't fun! I'd only be fun if you're a nerd!
2007-03-03 13:11:29 · answer #4 · answered by Bob 3 · 0⤊ 1⤋
Jeez, I'm not THAT smart!
2007-03-03 13:11:45 · answer #5 · answered by imtunacracker 1 · 0⤊ 1⤋