Evaporating sweat cools the body because evaporation absorbs 2.44 kJ per gram of water evaported. Estimate the mass of water that must evaporate from the skin to cool a body by 0.50 degrees C, if the mass of the body is 95 kg and its heat capacity is 4.01 J/g degree C. (Remember: convert 2.44 kJ to J and convert 95 kg to g).
I understand the answer is 78 g but I need help with step by step detail. Thank you.
2007-03-03 13:02:05 · 2 answers · asked by xxxladyxxx 1 in Science & Mathematics ➔ Chemistry
Part 1 is to calculate the heat needed to leave the body.
The formula is q = m Cp delta T, where q is the heat in joules.
You have the mass of 95,000 g. The Cp is 4.01 and the temp change is 0,5 C. Multiply across them to get q.
Part 2 is to calculate how much water has to evaporate to absorb this heat.
The formula is q = m Hv
The q is the answer from part 1.
m is the unknown and Hv is 2440 j / g.
Solve for m and you're done
The mass is un
2007-03-03 13:48:52 · answer #1 · answered by reb1240 7 · 0⤊ 0⤋
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2017-02-11 15:21:20 · answer #2 · answered by ? 4 · 0⤊ 0⤋