NEED HELP with a geometry problem. i will choose best answer for the one who can help!!!!?

Question

Here is the problem. I think i have it, but I'm not sure. Please help and show work.

The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field.

Answer 1

x=width
y=length=2(x)-5
then 2(2x-5)+2(x)=230
4x-10+2x=230
6x=240
x=40ft=width
y=2(x)-5=2(40)-5=75ft=length

Answer 2

Let the width be x

Twice the width means 2 times x which is 2x

The length will be 2x - 5

Perimeter (given) is 230 ft

To calc perimeter, its 2 length + 2 width, therefore

2(2x - 5) + 2(x) = 230

Then expand and factorise

4x - 10 + 2x = 230
6x - 10 = 230
6x = 230 + 10
6x = 240
x = 40

Therefore
Width = x = 40ft
Length = 2x - 5 = 2(40)- 5 = 75ft

Done =)

Answer 3

First draw a picture of a rectangle.Label the width,w. The length is then 2w - 5. The perimeter is the sum of all the sides, so add....(2w-5)+(2w-5)+w+w=230. Now solve the equation for w. 6w-10=230........6w=240.....w= 40 and the length is 75.

Answer 4

L (length) = 2w-5

W (width)

P (perimeter) = 2L + 2W = 230

2L + 2W = 230

Simplify to one variable,

2(2W-5) + 2W = 230

Apply Dist. Property,

4W-10 + 2W = 230

Combine like terms,

6W-10 = 230

Isolate variable,

6W-10 + 10 = 230 + 10
6W = 240
6W / 6 = 240 / 6
W = 40

Now, apply the formula for the length, and you get the answer.

L = 2W-5
L = 2*40-5
L = 80-5
L = 75

Check your answer:

40*2 + 75*2 = 230
80+ 150 = 230
230 = 230

Answer 5

First thing is to represent what you know mathmatically.
L=Length
W=width
P=Perimeter
Represent it like this :
L=2W-5
or like this:
W=(L+5)/2

The Perimeter is just L+L+W+W, since it is just a rectangle, which can be simplified to:
2(L+W)=230
At this point just substitute the values for L or W "W=(L+5)/2 or substitute L=2W-5"
If you do that then you reduce the number of unknown variables from 2 to 1.

Answer 6

ok. it goes like this:

230=X+X+(2X-5)+(2X-5)
OR
230=6X-10
add 10 to each side so you have
240=6X
divide each side by 6, so that
40=X
so 40 is your width, and your length would be
2(40)-5
which is 75

Answer 7

width=w
length=2w-5
P=230
P=2l+2w
230=2(2w-5)+2w
230=4w-10+2w
230=6w-10
240=6w
40=w
to find the length you plug 40 back into the equation for length.
length=2(40)-5
length=75 and width=40

Answer 8

My answer is erroneous, yet my technique is right. Midpoints are impressive. Gradient of line = (Y1-Y2)/(X1-X2) Gradient of XY = (40 8-sixteen)/(40 4-80 one) = -32/37 Gradient of YZ = (sixteen-sixty 9)/(80 one-ninety one) = fifty 3/10 Gradient of XZ = (40 8-sixty 9)/(40 4-ninety one) = 21/40 seven Medians are perpendicular bisectors of their lines. Median XB is a perpendicular bisector of YZ. Gradient of perpendicular bisector = -a million/gradient of line Gradient of XB = -a million/gradient of YZ = -a million/(fifty 3/10) = -10/fifty 3 Gradient of YC = -a million/gradient of XZ = -a million/(21/40 seven) = -40 seven/21 Gradient of ZA = -a million/gradient of XY = -a million/(-32/37) = 37/32 making use of the equation y-y1=m(x-x1), the place m is gradient of a line, Calculating the equation of XB (making use of coordinates of midpoint B): *be conscious: you should use the coordinates of any factor, as long because it somewhat is alongside line XB whilst y = fifty 3.5, x = seventy 5, m = -10/fifty 3, y-fifty 3.5 = -10/fifty 3(x-seventy 5) y = (-10/fifty 3)x + sixty seven+sixty 9/106 y = -0.1887x + sixty seven.651 Repeating this technique for YC and XA, YC: y-sixty 9.5 = -40 seven/21(x-fifty six.5) y = (-40 seven/21)x + 195+20/21 y = -2.238x + 195.952 ZA: y-32 = 37/32(x-sixty two.5) y = (37/32)x - 2577/sixty 4 y = a million.156x - 40.266 it style of sounds like your answer and my answer is diverse. it somewhat is advisable to information-examine the two our workings to verify if there are any errors. Now, what do you do once you decide directly to discover the intersection of two lines? All you actual choose is two simultaneous equations, that are the equations of the lines that intersect. hence, you have 3 lines that intersect at a easy factor, so which you would be able to decide on 2 out of the three for use as simultaneous equations. i decide on XB and YC: XB: y = -0.1887x + sixty seven.651 -- (a million) YC: y = -2.238x + 195.952 -- (2) Subst. (a million) into (2) -0.1887x + sixty seven.651 = -2.238x + 195.952 x = sixty two.607 whilst x = sixty two.607, y = -0.1887(sixty two.607) + sixty seven.651 y = fifty 5.837 Coordinates of the centriod are (sixty two.607, fifty 5.837). to check that my answer is right, I replace the values of the coordinates of the centriod into the Equation of ZA: y = a million.156x - 40.266 whilst y = fifty 5.837, Left Hand facet = fifty 5.837 whilst x = sixty two.607, perfect Hand facet = -a million.156(sixty two.607) - 40.266 = -112.640

Answer 9

Width - 40
Length - 75

Answer 10

why don't u try the example problems in the text book?