Consider a conical pendulum with an 79.0 kg bob on a 10.0 m wire making an angle of (theta) = 3.00° with the vertical (Fig. P6.9).
Figure P6.9
- http://www.webassign.net/pse/p6-13.gif
(a) Determine the horizontal and vertical components of the force exerted by the wire on the pendulum.
in the notation N i + N j
(b) What is the radial acceleration of the bob?
in m/s2 (toward the center of the path)
2007-03-03 11:01:25 · 2 answers · asked by bonkti 3 in Science & Mathematics ➔ Physics
Forces on the pendulum
T=W + Fc (vector addition)
Fc=Tsin(3)=Ni
Fc=m ac
T- tension
Fc - radial force
ac - radia acceleration
Fc= W tan(3.0)
Fc=m g tan (3.0)
Fc=79 x 8.81 x tan(3)=
Fc=40.6 N
and Nj=W=mg=79 x 9.81=775 N
T=Ni +Nj= 40.6 i + 775j N
and finally the radial acceleration
ac=Fc/m=40.6/79=0.51 m/s^2
2007-03-06 08:24:43 · answer #1 · answered by Edward 7 · 2⤊ 0⤋
Are you sure it's 3 deg and not 30?
a) (79*9.8*sin3) i + (79*9.8*cos3) j
b) v^2/10sin3
2007-03-03 19:21:09 · answer #2 · answered by DuckyWucky 3 · 1⤊ 0⤋