The following is a half-reaction. I need to know whether oxidation or reduction is involved.
ClO2(g)--->HClO3(ag)
The answer is Oxidized because Cl is changed from +4 to +5. Can someone break this down so i can understand please?
2007-03-03 10:56:08 · 3 answers · asked by Toothie 2 in Science & Mathematics ➔ Chemistry
If only I could scan a little diagram to you... But think of it this way: oxygen almost always ionizes to a minus 2 charge. In your ClO2, the oxygen accounts for minus 4 since there are 2 of them. So if your compond is neutral, the Cl must have a plus 4 charge. Now in the HClO3, you have 3 oxygens, each with their minus 2 charge, for a total of minus 6. On the positive side, you have hydrogen with a plus one charge. That leaves plus 5 on your chlorine, so it has been oxidized in the reaction.
2007-03-03 11:08:25 · answer #1 · answered by chemmie 4 · 0⤊ 0⤋
Oxidation and reduction always occur at te same time.
Cl went from +4 to +5, loss of an electron, oxidation
There is another half of the equation where something gained that electron, reduction
2007-03-03 19:04:07 · answer #2 · answered by science teacher 7 · 0⤊ 0⤋
its oxidation cause OH is added which has a charge of -1. so the Cl goes up to balance it. but i took chem and dont really know if thats completely correct.
2007-03-03 19:11:31 · answer #3 · answered by Tigre 1 · 0⤊ 0⤋