Couple of physics problems from hw?

Question

Problem 1:
http://img480.imageshack.us/img480/8757/problemanglezj1.gif
I got the first part of this question right which is 7.05666593e-11.But im doing something wrong in calculating the angle.
Fy= G(1.5)(3.5)/2.3^2 = 6.621e-11
Fx= G(1.5)(4.3)/4.2^2 = 2.43959e-11
so the angle is tan-1(fy/fx) = 1.217796181 degrees? but thats wrong :(

Problem 2:
http://img231.imageshack.us/img231/2783/1e1nne1.gif

Answer 1

Ok, i have read the problem, but it does seem your on track. are you sure your calculator is in the correct mode. i.e. in degrees mode not radian mode

Answer 2

a million) certainly all action is relative so it relies upon on what you chosen as 0 place and speed even nevertheless, the displacement is the replace from what you call the commencing factor and direction so the replace is the comparable. yet in a distinctive way of asserting "each and all the guidelines of physics could desire to be the comparable for anybody" difficult Q 2) speed V, a vector with length and direction = replace in in place (vector) according to unit time user-friendly V is the (D very final - D commence) / T and additionally T = t very final - t commence) yet in a distinctive thank you to assert user-friendly is (very final +preliminary ) / 2 so V user-friendly is ( V commence + V very final) /2 yet for that reason V commence = 0 Acceleration A = (V very final - v commence)/ T so the replace in V = A x T (contain the direction, turning counts as acceleration , later at school) the relation between D , V, A and T is " D very final = a million/2At^2 + V preliminary t + D commence" V user-friendly is 4.32 m/s /2 = 2.sixteen m/sec and additionally At= V very final by skill of V = A t : (4.32 m/s ) = A x 4.seventy two sec so A = V/t = 4.32 m/s/ 4.seventy two s = slightly below a million m/sec^2 understanding the conventional velocity and the time we get the full distance 2.16m/sec x 4.seventy two sec = approximately 9 m we've very final velocity, acceleration, finished time, user-friendly velocity and distance be conscious I consistently write the gadgets which multiply and "cancel" basically like numbers 3) difficult be conscious there are 2 circumstances that each and each use D = V t the D is a million mile in the two the sluggish time is D / V sluggish = t sluggish additionally t sluggish = (t quickly + 15 sec) quickly time = (sluggish time - 15 sec) and V quickly = (V sluggish + 7.7 mi/h) one approach is shop guessing. attempt distinctive speeds and circumstances and get a chart till you locate one that works for sure the quickly time would be unable to be 0, this could artwork even nevertheless it demands a great sort of guesses i could desire to be getting old. i attempted to describe this intimately for the final a million/2 hr and shop blending myself up. i'm going to artwork on a sparkling undemanding clarification. perhaps somebody else could have an undemanding answer first e-m me later