finding a side of a right angled triangle?

Question

there is a right angled triangle labelled ABC

i have the length of the hypotenuse (AC) - 12.6m
and the length of angle A - 41deg

i have to find the length of the side AB

How do i do this?

Answer 1

Have a look at the link for more details, but a quick description is:

We want the length of the side adjacent to the angle A.

In ar right-angled triangle

COS(angle)=adjacent/hypotenuse

Therefore:

adjacent = COS(angle)*hypotenuse

= COS(41 deg) * 12.6

= .755 * 12.6 = 9.509. Rounding up to 9.5 for the same decimal places as the question.

Answer 2

the undeniable fact that Y = ninety° makes issues greater handy. keep in mind the definition of the tangent of an perspective in a stunning triangle: the ratio of the choice side to the adjacent side. (O/A, or opp/adj, for short.) the choice side of perspective side XY; the adjacent side is YZ, which has length 5. The tangent of Z is then XY/YZ, or XY/5. for the reason that tan(fifty 8°) = XY/5, then XY = 5·tan(fifty 8°), approximately 8.0. The secant of Z is the ratio of the hypotenuse to the adjacent side (H/A, or hyp/adj). sec(fifty 8°) = XZ/YZ = XZ/5. for this reason 5·sec(fifty 8°) = 5·(a million/cos(fifty 8°)), approximately 9.4.

Answer 3

A=41
B=90
C=?

41+90=131

180-131=49

C=49

Hope that helps because I am horrible at Geometry.

Answer 4

you use the hypotenus theorem, i really can remeber how you come about it, but google it to find the formular. here is a link you should go to, it automatically solves it for you. Good luck.

http://www.1728.com/trig.htm

Answer 5

AB = ACcos41º = 12.6x 0.755 = 9.5

Answer 6

(A x A) + (B x B) = (C x C) find what A squared and C squared is and B squared will be the difference.

Answer 7

Here:

Cosine(41)= (x/12.6)
x=(Cosine(41)(12.6))
x=9.509 m

Hope that helps.

Answer 8

A^2 +B^2=Pie *AC
_______________
41 * AB^2

Answer 9

you have to use tangent

Answer 10

www.MAth.com