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Hypertonic and hypotonic?
a dialysis bag contain an aqueous solution of .3 M lucose .2M fructose, and .1M glucose is immersed in an aqueous solution of .4M maltose and .3M fructose. the dialysis bag is permeable to water and monosacchrides but is completely impermeanble disacchrides. describe how the distribution of water and sugars will change. explain your reasoning.
please help me . i am stupid in biology i have no clue . thanks in advance

2007-03-03 03:33:20 · 1 answers · asked by phong pham 2 in Science & Mathematics Biology

1 answers

If the bag is impervious to dissacharides, then only fructose, glucose and water will migrate from one solution to the other. If I know the volumes of the bag and solution, I could calculate the final concentrations. I can tell you that fructose will migrate into the dialysis bag because the concentration in the aqueous solution is greater than in the dialysis bag. Maltose will not migrate because it is a dissacharide. Glucose will migrate out of the dialysis bag because the aqueous solution does not contain any. Water will probably migrate out of the dialysis bag because the aqueous solution is hypertonic with respect to the dialysis bag. I'm not quite sure what lucose is. Is that a typo?

2007-03-03 03:59:36 · answer #1 · answered by misoma5 7 · 0 0

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