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find the ninth term of the expansion (a-1)^13?

answers:
1287a^4
1287a^5
a^5
-a^9

2007-03-03 03:31:34 · 2 answers · asked by julie s 1 in Science & Mathematics ➔ Mathematics

2 answers

The formula would be 13C8 (a)^5(-1)^8

2007-03-03 03:38:54 · answer #1 · answered by hayharbr 7 · 1⤊ 0⤋

= C(13,8) a^5(-1)^8 = 1287a^5

2007-03-03 11:50:26 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋

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