express the following numbers as products of their prime factors.
i) 56
ii)84
find the highest common factor of 56 and 84
2007-03-03 01:57:41 · 5 answers · asked by jenny 1 in Science & Mathematics ➔ Mathematics
56/2 = 28
28/2 = 14
14/2 = 7
7 is prime
So 56 = 2³ * 7
Similarly 84 = 2²*3*7
Looking for the largest product common to both
numbers, we see that the HCF of 56 and 84
is 2²*7 or 28.
2007-03-03 02:04:07 · answer #1 · answered by steiner1745 7 · 0⤊ 0⤋
56 = 2 x 2 x 2 x 7
84 = 2 x 2 x 3 x 7
So the highest common factor is 4 times 7 =28
2007-03-03 10:02:08 · answer #2 · answered by J 5 · 1⤊ 0⤋
56 = 2 x 2 x 2 x 7
84 = 2 x 2 x 3 x 7
HCF = 2 x 2 x 7 = 28
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2007-03-03 10:50:48 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
56 = 2 * 2 * 2 * 7
84 = 2 * 2 * 3 * 7
Thus HCF = 2 * 2 * 7 = 28
lcm = 2 * 2 * 2 * 3 * 7 = 168
2007-03-03 10:02:27 · answer #4 · answered by FedUp 3 · 0⤊ 0⤋
56=2x2x2x7
84=2x2x3x7
hcf would be 2x2x7=28
2007-03-03 10:35:19 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋