slightly stuck again. firstly i need help to complete the equation and balance it and then i need to work out how many moles each reactant has. but i cant! please help.
2007-03-03 01:55:17 · 4 answers · asked by tomw91 2 in Science & Mathematics ➔ Chemistry
i need all working out please
2007-03-03 02:10:36 · update #1
CaCO3+H2SO4 ---> SO4Ca+H2O+CO2
you see that one mole of CaCO3 gives one mole ofCO2 (1 is for all the constituants)
the molecular mass of CO3Ca is 12+48+40 =100
50g corresponds to 50/100 =0.5 mole
And 0.5 mole at 0°C = 22.4 /2 =11.2L
2007-03-03 02:22:06 · answer #1 · answered by maussy 7 · 1⤊ 0⤋
If your teacher had actually tried this experiment before setting you the problem, he would have found that calcium carbonate does not react at all well with sulphuric acid. If you're lucky the whole tube siezes up in a congealed mass - it's called Plaster of Paris! Insoluble calcium sulphate coats the marble chips (or powder) and stops any further reaction.
2007-03-03 05:10:55 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋
22 g (0.5 moles)of carbondioxide is produced as 50 g calcium carbonate is 0.5 moles and it occupies a volume 11.2 litres at ntp.
2007-03-03 02:41:40 · answer #3 · answered by Venkateswara Rao K 2 · 0⤊ 1⤋
49gms
2007-03-03 02:01:24 · answer #4 · answered by prannayj 2 · 0⤊ 1⤋