2007-03-03 01:05:14 · 6 answers · asked by rave_thehotice 1 in Science & Mathematics ➔ Mathematics
I gather that you mean (a + b)^3 ('^' stands for 'to the power of')
(a + b)^3 = a^3 + b^3 + 3a^2b + 3ab^2
Yes, this is an identity because it is true for all values of a and b. An equation which is true for all real values of the variables involved is called an identity.
If you mean 3(a + b),
3(a + b) = 3a + 3b which is also an identity as any value of a and b would satisfy this equation.
2007-03-03 01:53:40 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
As any valyes of a and b wouldd satisfy (a+b)^3=a^3+3a^2b+3ab^2+b^3,it is an identity
Even if it is (a+b)*3,it would still be an identity
2007-03-03 01:16:52 · answer #2 · answered by alpha 7 · 0⤊ 0⤋
well the answer would be 3a+3b, but i dont get the identity part.
2007-03-03 01:16:08 · answer #3 · answered by builtff 2 · 0⤊ 0⤋
(a+b)*3 = 3a+3b
2007-03-03 01:18:55 · answer #4 · answered by Anonymous · 0⤊ 0⤋
(a+b)(square)= a(square) + 2ab + b(square)
(a+b)(a+b)= a(square) + ba+ ab + b(square)
(a+b)(cube)= ???
(a+b)(a+b)(a+b)= (a+b)(a(square) + 2ab + b(square))
(a+b)(a(square)+ 2ab + b(square))= a(cube) + 2a(square)b + ab(square) + ba(square) + 2ab(square) + b(cube)
lawl, wild guess
2007-03-03 01:18:44 · answer #5 · answered by Yus B 2 · 0⤊ 0⤋
No
Please give me best answer thanks!
2007-03-03 03:11:50 · answer #6 · answered by Anonymous · 0⤊ 0⤋