x^2 – 9x + 14
27x^3 – 64
42x^3 + 51x^2 – 18x
2007-03-03 00:04:07 · 5 answers · asked by rosecrashers1365 2 in Science & Mathematics ➔ Mathematics
1.(x-7)(x-2)
2.(3x-4)(9x^2+12x+16)
3.3x(14x^2+17x-6)
2007-03-03 00:13:03 · answer #1 · answered by shilpu 2 · 0⤊ 0⤋
x^2-9x+14 = x^2-7x-2x+(7x2)=x(x-7)-2(x-7)= (x-2)(x-7)
27x^3-64 = (3x)^3 - 4^3 use the formula a^3-b^3=(a-b)(a^2+ab+b^2) and solve
42x^3+51x^2-18x= 3x(14x^2+17x-6) =3x(14x^2+21x-4x-6)
=3x[ 7x(2x+3)-2(2x+3)]=3x[ (2x+3)(7x-2)]
2007-03-03 08:21:39 · answer #2 · answered by Reema 2 · 0⤊ 0⤋
here you go:
x^2-9x+14
= x^2-2x-7x+14
=x(x-2)-7(x-2)
= (x-7)(x-2)
you get it?
next one:
i don't think it can be factored. if it can then i'm not sure how.sorry.
lastly:
42x^3+51x^2-18x
= x( 42x^2+51x-18)
=x( 42x^2+63x-12x-18)
=x( 21x(2x+3)-6(2x+3))
= x(21x-6)(2x+3)
i hope that this helped you.
2007-03-03 08:27:30 · answer #3 · answered by this is me! 3 · 0⤊ 0⤋
x² - 9x + 14 = 0
x² - 7x - 2x + 14
x(x - 7) - 2(x - 7)
(x - 2)(x - 7)
- - - - - - -s-
2007-03-03 10:07:46 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
a)
(x-7)(x-2)
b)
(3x-4)(9x^2+12x+16)
c)
(21x-6)(2x-3).x
2007-03-03 08:25:56 · answer #5 · answered by jonny k 3 · 0⤊ 0⤋