2007-03-02 22:42:31 · 16 answers · asked by Pavithra M 1 in Science & Mathematics ➔ Mathematics
None of the above.
3 and 2 are prime and the difference is 1.
5 and 2 are prime and the difference is 3.
11 and 2 are prime and the difference is 9.
If however you meant odd prime which does not include the number 2 (2 was not always considered to be prime anyways) then my answer would be modified.
All of the above numbers cannot be the difference provided both x and y are ODD prime.
2007-03-02 23:00:26 · answer #1 · answered by Fin 5 · 0⤊ 0⤋
In mathematics, a prime number (or a prime) is a natural number that has exactly two (distinct) natural number divisors, which are 1 and the prime number itself. There exists an infinitude of prime numbers, as demonstrated by Euclid in about 300 B.C.. The first 30 prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, and 113.
So, as it could be easily noticed, the answer is that (A), (B), or (C) COULD be the difference between (x) and (y) prime numbers.
2007-03-02 22:58:18 · answer #2 · answered by Dr. Tamer Lokman 3 · 0⤊ 1⤋
(A) is false, because 2 and 3 are prime numbers, and their difference is 1.
(B) is false, because 2 and 5 are prime numbers, and they differ by 3.
(C) is false, because 2 and 11 are prime numbers, and they differ by 9.
Your answer is none of the above. I'm guessing there's some hidden condition that you either forgot to write down or the question didn't account for.
That makes (A) the most likely candidate, should the condition be for prime numbers greater than 2.
2007-03-02 22:46:31 · answer #3 · answered by Puggy 7 · 2⤊ 0⤋
All three cannot be the difference between two prime numbers.
Except 2, all prime numbers are odd.
And, an odd number plus odd number is even.
So, x + 9 or y + 9 = even number.
And an even number cannot be prime.
So, none of the options are correct.
Ans : (D) None of these.
2007-03-02 22:51:48 · answer #4 · answered by nayanmange 4 · 0⤊ 1⤋
If the two exponents are gently divisible by 3, then the product must be a suited cube. permit a and b be constructive entire numbers as coefficients. permit x, y are your 2 primes. permit m, n be 2 exponents divisible by 3. Then the final expression may well be: a(x^m)b(y^n) Take the cube root of the x and y words. a(x^m/3)b(y^n/3) this might effect in a suited cube on account that the two m and n are divisible by 3. c (6,9) and d (3,12) have exponents divisible by 3 and are subsequently suited cubes.
2016-12-18 04:42:57 · answer #5 · answered by ? 4 · 0⤊ 0⤋
Take x as 3 and y as 2
the difference will be 1.So, (A)1 IS NOT THE ANSWER
Take x as 5 and y as 2
the difference will be 3.So, (B)3 IS NOT THE ANSWER
Take x as 11and y as 2
the difference will be 9.So, (B)3 IS NOT THE ANSWER
HENCE,THERE SHOULD BE ANOTHER OPTION
(D)NONE OF THE ABOVE
THE ANSWER IS (D)
2007-03-02 23:59:19 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the answer is 9
2007-03-02 22:52:18 · answer #7 · answered by slimshady 1 · 0⤊ 0⤋
C
all false
looks like u fuhgot to put the D option
2007-03-02 22:52:48 · answer #8 · answered by yash_slim_shady 2 · 0⤊ 0⤋
1cannot be the differince of prime numbers
2007-03-02 22:47:20 · answer #9 · answered by Anonymous · 0⤊ 1⤋
Don't really know, but I think all can be the difference.
2007-03-03 07:40:38 · answer #10 · answered by Arc 2 · 0⤊ 0⤋