You need to expand the two by multiplying all the different combinations then adding the result:
1) multiply the first terms of each parenthesis:
-6 * -5 = +30
2) multiply the last terms of each parenthesis:
7t * 9t = 63t^2
3) multiply the first term from the first parenthesis by the second term from the second parenthesis:
-6 * 9t = - 54t
4) multiply the second term from the first parenthesis by the first term from the second parenthesis:
7t * -5 = -35t
now, add all of the answers together to get your final answer
= 30 + 63t^2 + (-54t) + (-35t)
= 30 + 63t^2 - 54t - 35t
= 30 + 63t^2 - 89t
but usually we write with bigger powers first, like:
63t^2 - 89t + 30
2007-03-02 18:53:27
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answer #1
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answered by vanchuck 2
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I was taught to multiply binomials do the following:
F.O.I.L.
First terms multiplied
Outer terms multiplied
Inner terms multiplied
Last terms multiplied
--Combine like terms--
F -6 x -5 = 30
O -6 x 9t = -54t
I 7t x -5 = -35t
L 7t x 9t = 63t^2
63t^2 - 89t + 30
2007-03-02 19:00:29
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answer #2
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answered by CollegeMeg 2
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(- 6 + 7T)(- 5 + 9T) =
30 + 35t + 54t + 63t² =
30 + 89t + 63t²
- - - - - - - - - -s-
2007-03-03 02:22:42
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answer #3
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answered by SAMUEL D 7
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I guess you want the expanded expression, for homework most likely. 30-89t+63t^2.
2007-03-02 18:57:46
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answer #4
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answered by revolutionist1985 2
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63t squared - 89t + 30
2007-03-02 18:58:05
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answer #5
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answered by Obs T 2
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63t^2-89t+30
2007-03-02 19:07:03
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answer #6
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answered by paul13051956 3
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jeez. idiot. be on the show: "Are you Smarter than a 5th Grader?"
30 - 54t - 35t + 63 t^2
30 - 89t + 63 t^2
63t^2 - 89t + 30
2007-03-02 18:59:26
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answer #7
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answered by JtoJ 4
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= 30 - 54.t - 35.t + 63.t² = 63.t² - 89.t² + 30
2007-03-02 18:55:53
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answer #8
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answered by Como 7
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30-89t+63t²
2007-03-02 18:54:23
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answer #9
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answered by JD2B 2
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30-54t-35t+63t^2
30-89t+63t^2
2007-03-06 16:15:31
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answer #10
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answered by someone 2
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