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2007-03-02 18:50:29 · 14 answers · asked by Vivian 1 in Science & Mathematics Mathematics

14 answers

You need to expand the two by multiplying all the different combinations then adding the result:

1) multiply the first terms of each parenthesis:
-6 * -5 = +30

2) multiply the last terms of each parenthesis:
7t * 9t = 63t^2

3) multiply the first term from the first parenthesis by the second term from the second parenthesis:
-6 * 9t = - 54t

4) multiply the second term from the first parenthesis by the first term from the second parenthesis:
7t * -5 = -35t

now, add all of the answers together to get your final answer

= 30 + 63t^2 + (-54t) + (-35t)
= 30 + 63t^2 - 54t - 35t
= 30 + 63t^2 - 89t

but usually we write with bigger powers first, like:

63t^2 - 89t + 30

2007-03-02 18:53:27 · answer #1 · answered by vanchuck 2 · 1 0

I was taught to multiply binomials do the following:

F.O.I.L.
First terms multiplied
Outer terms multiplied
Inner terms multiplied
Last terms multiplied
--Combine like terms--

F -6 x -5 = 30
O -6 x 9t = -54t
I 7t x -5 = -35t
L 7t x 9t = 63t^2


63t^2 - 89t + 30

2007-03-02 19:00:29 · answer #2 · answered by CollegeMeg 2 · 0 0

(- 6 + 7T)(- 5 + 9T) =

30 + 35t + 54t + 63t² =

30 + 89t + 63t²

- - - - - - - - - -s-

2007-03-03 02:22:42 · answer #3 · answered by SAMUEL D 7 · 0 0

I guess you want the expanded expression, for homework most likely. 30-89t+63t^2.

2007-03-02 18:57:46 · answer #4 · answered by revolutionist1985 2 · 0 0

63t squared - 89t + 30

2007-03-02 18:58:05 · answer #5 · answered by Obs T 2 · 0 0

63t^2-89t+30

2007-03-02 19:07:03 · answer #6 · answered by paul13051956 3 · 0 0

jeez. idiot. be on the show: "Are you Smarter than a 5th Grader?"

30 - 54t - 35t + 63 t^2

30 - 89t + 63 t^2

63t^2 - 89t + 30

2007-03-02 18:59:26 · answer #7 · answered by JtoJ 4 · 0 1

= 30 - 54.t - 35.t + 63.t² = 63.t² - 89.t² + 30

2007-03-02 18:55:53 · answer #8 · answered by Como 7 · 0 1

30-89t+63t²

2007-03-02 18:54:23 · answer #9 · answered by JD2B 2 · 0 0

30-54t-35t+63t^2
30-89t+63t^2

2007-03-06 16:15:31 · answer #10 · answered by someone 2 · 0 0

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