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HELP!!!....

Im interested if this amino acid Alanine's R group can donate a

proton in a aqueous solution. To my understanding it can donate and recieve protons in an aqueous solution. Im more interested in the donating part though. Can anyone verify this.

If you can provide a link to your info that would be extremely helpful aswell.

thanks alot

2007-03-02 15:02:42 · 4 answers · asked by geo 1 in Science & Mathematics Biology

4 answers

NO, the R group cannot, it is an acid, and thus can donate a proton, but only from the alpha carboxylic acid at a pH of 2.35 and from the alpha amino at 9.87, which means at physiolocial pH = ~7.4 the carboxilic proton is donated and the alpa amino is not, but the R group will abosolutly not donate a proton, you can take that to the bank.

2007-03-02 15:55:48 · answer #1 · answered by jason e 2 · 1 0

you opt for to make certain an ICE chart (I = initial, C = replace, E = equilibrium) for a weak acid. HB = cinnamic acid on the accurate of the chart, you've HB --> H+ + B- The initial volume of HB is a million.6*10^-3 The replace for HB is -x, even as the replace for H+ and B- is +x The equilibrium volume for HB is a million.6*10^-3 - x The equilibrium volume for H+ is x. Ka = [H+]^2/[HB] So Ka = x^2/(a million.6*10^-3 - x) because x is this style of small volume, it will be removed from the denominator with out causing a lot disturbance. so that you're left with Ka = x^2/a million.6*10^-3 After plugging in Ka and fixing for x, you get: x = 2.40 3*10^-4 = [H+] -log ([H+]) = pH pH = 3.sixty one

2016-11-27 01:18:10 · answer #2 · answered by niang 4 · 0 0

Do not see why not. The end of R group is NH3+.

PS I defer to the functional biologist, Jason E.

2007-03-02 15:25:03 · answer #3 · answered by Anonymous · 0 0

not called an amino "acid" for nothing :)

2007-03-02 15:34:47 · answer #4 · answered by audionaut 3 · 1 0

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