A toy rocket-launcher contains a spring with a spring constant of 35 N/m. How far must the spring be compressed to store 1.5 Joules of energy.
I don't understand this question.
Please help me.
2007-03-02 13:20:52 · 3 answers · asked by vicky p 1 in Science & Mathematics ➔ Physics
Spring energy = - 0.5 k x^2
Therefore,
- 0.5 (35 N/m) (x^2) = - 1.5 J
Note: 1 J = 1 N*m, and the minus sign indicate absorbing energy.
x^2 = 1.5 / (35 * 0.5) [m^2]
x = 0.293 m
2007-03-02 14:24:11 · answer #1 · answered by Ben 3 · 2⤊ 0⤋
Toy Rocket Launcher
2016-10-02 21:25:55 · answer #2 · answered by brinton 4 · 0⤊ 0⤋
When a spring is compressed it stores potential energy. The potential energy is equal to
PE = 1/2 k x^2, where k is the spring constant and x is the displacement of the spring
if we solve for x we get
x = sqrt ( 2PE / k ) = sqrt (2 x 1.5 / 35 ) = sqrt (.085714)
x = .29 meter = 29 centimeters
2007-03-02 14:25:35 · answer #3 · answered by ignoramus_the_great 7 · 2⤊ 0⤋