What is an experiement I can conduct to show how surface area to volume ratio affects the rate of diffusion?

Answer 1

How about, take two or more graded cylinders of equal diameter but different depth. This way, the surface area remains the same, but the volume changes. Then, pour drops of a red dye into the water and time how far down each gradation the dye diffuses. The gradations are equal and therefore gradation/time gives a measure of rate of diffusion. You also control for surface area effects, but surface:volume ratio changes.

Answer 2

you obtain the quantity applicable, yet for the exterior section you forgot to count huge type various of the surfaces. To calculate floor section, you're able to upload up the part of ALL surfaces of the solid. hence, featuring the two semicircular bases (applicable and backside), the curved exterior (25.a million in^2), and the at as quickly as ingredient opposite the curve. applicable and backside A = (a million/2 Pi r^2) = 2Pi, cases 2 = 4Pi = 12.6 in^2 Curved exterior A = a million/2 (2Pi r) h = 8Pi = 25.a million in^2 at as quickly as ingredient = 4in * 4in = 16in^2 entire = fifty 3.7 in^2 wish this helped!

Answer 3

Try this site:

http://www.accessexcellence.org/AE/SH/NSTA_SF/brown.html