Find the length and width of the playground?

Question

the area of a children's rectangular playground is 500 sq.meters. the length is 5 meters longer than the widthl Find the length and width of the playground

Answer 1

Width: w
Length: w + 5
Length * Width = Area
(w + 5) * w = 500
w^2 + 5w = 500
w^2 + 5w – 500 = 500 – 500
w^2 + 5w – 500 = 0
w^2 + 5w + (-500) = 0
(w)(w) + (25w – 20w) + (-20)(25) = 0
(w – 20)(w + 25) = 0
w > 0
w – 20 = 0
w – 20 + 20 = 0 + 20
w = 20
w + 5 = 20 + 5 = 25
the dimensions of the rectangular playground are 25 length by 20 width.

Answer 2

x=width
x+5=length
(x)(x+5)=500 because Area=length X width
x^2+5x-500=0
(x+25)(x-20)=0 Finish the operation and you have the answer.
X=20=width
x+5=25=length

Answer 3

A = L * W
L=W+5

500 m^2 = W * (W+5)
500 = w^2 + 5w
w^2+5w-500=0
(w+25)(w-20)=0
w= -25,20
since you can't have a negative length, width = 20.

plug back in and length is 25. =)

Answer 4

Area = L x W
500 = 5 x W (substitute)
/5 /5 (divide each side by 5)
100 = W

Length= 5
Width= 100


CHECK
Area = L x W
Area = 5 x 100
5 x 100 = 500

Answer 5

the easiest way to understand it is this:

the area of an object = the length x the width

you know the area, and the length (its the width you want to find)

so, if you know your maths on how to change the above equation, then the answer is this:

area of object
------------------ = width (500/5= 100)
length