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The current in a loop circuit that has a resistance of R_1 is 2.00 A. The circuit is reduced to a 1.60 A when an additional resistor R_2=3.00 ohm is added in series with R_1. What is the value of R_1.

2007-03-02 09:06:18 · 3 answers · asked by hpage 3 in Science & Mathematics Physics

3 answers

I = V / R
find the voltage in the first part
V = I * R = 2R

now plug it in to the second part resistors are in series and voltage is the same
2R = 1.6A (R + 3ohm)
R = 7.5 ohms

2007-03-02 12:44:11 · answer #1 · answered by John 5 · 0 1

Your teacher must have taught you Ohms law. If not, look it up. There, you will find your answer.

2007-03-02 17:41:11 · answer #2 · answered by Jmeller 2 · 0 0

quit cheating on your homework!,look it up and learn,youll live to appreciate it,lol

2007-03-02 17:13:39 · answer #3 · answered by jeffers 1 · 1 0

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