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The fish in a population of parrot fish may have scales of one or two colors. Some fish have blue scales and some have green. Twenty-five percent of the population is homozygous recessive (bb) for green scales. The remaining 75 percent of the population have blue scales, but you don't know if they are heterozygous (Bb) or homozygous dominant (BB). Assuming the population is in Hardy-Weinberg equilibrium, use p+q=1 and the Hardy-Weinberg equation (p2+ 2pq+q2=1) to figure out the genotypic frequencies for BB and Bb. Show your steps throughout.

the p2 and q2 is squared*

2007-03-02 08:46:10 · 2 answers · asked by live~laugh~love 1 in Science & Mathematics Biology

2 answers

Good question.
(p + q)² = p² + 2pq + q² = 1;

(bb) = b² = 25% = .25;
b = √.25 = .5, therefore B = .5.

You can find the genotypic frequencies for BB and Bb as follows:
BB = .5² (p²) = .25, and
Bb = 2 × .5² (because it's 2pq) = .5

2007-03-05 18:33:38 · answer #1 · answered by Esse Est Percipi 4 · 0 0

You know, you've asked a whole series of homework questions here. You really do need to read your book and see if you can work out these problems. This one, in particular, will be very easy once you try to understand the material.

If there's some aspect that you're stuck on, feel free to ask, and I think people will be willing to help you understand. But, asking others to just do your homework for you defeats the purpose of homework in trying to help YOU learn the material.

2007-03-02 16:50:24 · answer #2 · answered by hcbiochem 7 · 1 1

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