(2x-1)²
= (2x-1)(2x-1)
= 4x² - 2x - 2x + 1
= 4x² - 4x + 1
2007-03-02 04:13:09
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answer #1
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answered by Anonymous
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It depends what you mean by "removing the brackets"
The normal way: see postings by cc and heather8875.
(2x-1)² = (2x-1)*(2x-1) =
(2x*2x) + (-1*2x) + (2x*-1) + (-1*-1) =
4x² -4x +1
If you mean, removing the bracket without changing anything else, then you get
2x-1²
= 2x - 1*1 = 2x - 1
(The second way makes no mathematical sense -- in other words, removing the brackets in this fashion changes the validity of the equation).
2007-03-02 04:22:22
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answer #2
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answered by Raymond 7
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Removing the brackets leaves you with 2x-1.
Only the 1 is squared and 1 squared is 1.
2007-03-02 04:17:05
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answer #3
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answered by Kenny 3
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If you remove the bracket then the following expression hold
2x-1² , which is equal to 2x - 1.
2007-03-02 04:14:07
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answer #4
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answered by The exclamation mark 6
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4
2007-03-02 04:12:13
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answer #5
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answered by Anonymous
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The answer can be find out by using the following relation.
(a-b)^2=(a+b) (a-b).
byusing this relation for the said question the answer comes out to be
=(2x+1) (2x-1)
I think this can satisfy you.
2007-03-02 04:15:08
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answer #6
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answered by deekay s 2
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(2x - 1)^2 = (2x - 1)(2x - 1)
use the FOIL method to find:
4x^2 - 4x + 1
2007-03-02 04:13:15
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answer #7
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answered by Mathematica 7
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B. C isn't a polynomial. Polynomial potential extra effective than one term. and the way can polynomials be monomials. MONO potential ONE. POLY potential MANY. do no longer pay attention to the different idiots. A monomial is a unmarried term which has NO plus sign (+) or minus sign (-) between entries. it must be issues like 13, 3x, -fifty seven, x², 4y², -2xy, or 520x²y² yet no longer (2x+7) or (4x²-2x).
2016-12-18 13:45:30
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answer #8
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answered by ? 4
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4x² - 4x + 1
(2x-1)² = (2x-1)*(2x-1)
then use FOIL=> First Outside Inside Last
=2x*2x + 2x*(-1) + (-1)*2x + (-1)*(-1)
=4x² - 4x + 1
2007-03-02 04:16:20
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answer #9
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answered by Nick 3
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remove the brackets and you have 2x - 1squared, which is 2x-1.
2007-03-02 04:17:30
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answer #10
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answered by cornettofile 1
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