2007-03-02 02:32:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Assuming 100g of the compound,
there would be 56.4g of Mn and 43.6g of S.
no of moles of Mn
= mass / Ar
= 56.4 / 54.9
= 1.027 mol
no of moles of S
= mass / Ar
= 43.6 / 32.1
= 1.36 mol
mole ratio of Mn : S = 3 : 4
Therefore empirical formula is Mn3S4.
2007-03-02 02:38:28 · answer #1 · answered by donteatflowers 2 · 0⤊ 0⤋
Say the number for Mn is x and the number for S is y.
54.9x/(54.9x + 32y) = 0.564
Therefore 4x = 3y
The lowest possible numbers that satisfy that equation is x=3 and y=4
So we have Mn3S4.
2007-03-02 10:47:02 · answer #2 · answered by Agent Smith 2 · 0⤊ 0⤋
56.4/12 43.6/11
4.7/3.96 3.96/3.96
1 1
answer=MnS
2007-03-02 10:41:33 · answer #3 · answered by jay gal 3 · 0⤊ 0⤋
the compund proably dont exist, buts its Mn2S3
2007-03-02 10:41:10 · answer #4 · answered by louzadodude 2 · 0⤊ 0⤋