2007-03-02 02:10:04 · 6 answers · asked by masteronan 2 in Science & Mathematics ➔ Mathematics
vertical asymptotes are when the denominator = 0.
so.... you have a vertical at x=0 in this case.
2007-03-02 02:15:12 · answer #1 · answered by Mathematica 7 · 1⤊ 1⤋
Finding the vertical asymptote deals with the denominator, which means the denominator cannot be zero:
x+4
Next, you set that to zero:
x+4=0
Subtract 4 from both sides:
x=-4
The vertical asymptote is -4.
2007-03-02 03:43:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋
As you have it written, the asymptote is at x = 0.
But if you mean f(x) = 17/(x+4), then the asymptote is at x = -4.
2007-03-02 02:26:31 · answer #3 · answered by Anonymous · 1⤊ 0⤋
2 answers which is correct ??
the problem is the question
is it (17/x) + 4 as assumed by first reply
or is it 17/(x+4) as assumed by second reply
2007-03-02 02:30:33 · answer #4 · answered by wimafrobor 2 · 1⤊ 0⤋
vertical assimptote exists at x = -4
vertical asimptote exists where the denominator equals to zero, so you must equalise the whole denominator
x + 4 = 0
solving the equation we get
x = -4
2007-03-02 02:21:35 · answer #5 · answered by AQ - מלגזה 4 · 1⤊ 1⤋
x=-4 because x=4 is a point of discontinuity and lim f(x) x=>-4 is infinity
2007-03-02 05:28:58 · answer #6 · answered by santmann2002 7 · 1⤊ 0⤋