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AGBr 8.8X106-7 mol L^-1?
and PbCrO4,1.3x10^-7 mol L^-1

2007-03-01 21:45:56 · 2 answers · asked by tikki 2 in Science & Mathematics Chemistry

2 answers

.. .. .. .. .. AgBr <=> Ag+ +Br-
Dissolve .. s
Produce .. .. .. .. .. .. s .. .. s

Ksp= [Ag+][Br-]= s^2= (8.8*10^-7)^2 =7.74*10^-13

Similarly

Ksp= [Pb+2][CrO4(-2)]= s^2 =(1.3*10^-7)^2 =1.69*10^-14

2007-03-01 21:53:19 · answer #1 · answered by bellerophon 6 · 0 0

Ksp(AgBr)=(solubility)^2
similarly for PbCrO4

2007-03-01 21:55:00 · answer #2 · answered by know it 2 · 0 0

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