Titration, please help!?

Question

Question: Determine the average molarity of the [unknown] acid solution by using the difference in volume of NaOH added between the first inflection point (i'm guessing they're talkin bout the equivalence point) and the seconf inflection point??

btw...this is a titration lab and i have to try and identify the unknown acid, which *hint* is a polyprotic acid....i just don't have a clue where to start...what equation should i, could i use? ANY IDEAS!! whatever you have...help!

Answer 1

Use the formula M1 = (M2 x V2) / V1

Where
M1 = Molarity of the acid
V1 = Volume of the acid
M2 = Molarity of the NaOH
V2 = Volume of NaOH titrated between inflection points

Answer 2

A titration is used while a answer of straightforward concentration would be further to and react with yet another fabric it particularly is of unknown concentration. the quantity of the addion of the answer has to have the means to be measured. The straightforward concentration fabric would desire to react in a straightforward share to the unknown fabric so as that the quantity of the unknown would be desperate. There would desire to be some thank you to understand while the unknown has been totally fed on so as that extra of the conventional answer isn't further. permit's say the reaction of the conventional, o.k. to the unknown, U is two:a million (2 moles ok reacts with a million mole U). permit's anticipate that the conventional concentration is 0.a million M and that we consume 35 ml of the answer interior the titration. this implies that we fed on 35 ml X 0.a million mmole/ml = 3.5 mmole of ok. because of the fact of the two:a million ratio, this implies there's a million.seventy 5 mmoles of U interior the pattern. Titration is used while there's a sparkling, straightforward molar ratio of straightforward to unknown, while there's a thank you to verify end ingredient, and while the reaction is speedy.