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An object slides down an inclined plane of angle 20° and of incline length 3 m. If the initial speed of the object is 3 m/s directed down the incline, what is the speed at the bottom? Neglect friction.

2007-03-01 14:46:20 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

because the velocity changes, we have an acceleration.
a=Fnet/m

draw a FBD and you'll see that Fweight(x) of the object is the net force.
a = Fweight(x) / m

break down Fweight(x)
Fweight(x) = sin(20)mg

a = sin(20)mg / m
the mass cancel out
a = sin(20)g
a = sin(20)9.8
a = 3.35m/s^2

Vf^2 = 2ad + Vo^2
Vf^2 = 2(3.35)(3) + 0^2
Vf^2 = 20.1
Vf = 4.48m/s

hope this helps

2007-03-01 15:16:51 · answer #1 · answered by      7 · 0 0

At the bottom the mass has a velocity of 5.4 m/sec. (directed down the incline of course).

Zeo... seems OK except about 5 lines from the bottom he carelessly "drops" your initial velocity; otherwise his answer would agree with mine.

2007-03-01 15:21:20 · answer #2 · answered by answerING 6 · 1 0

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