A second point was translated4 units down and 6 units to the left. It also arrived at (-1,-1). What were the original coordinates(t,r) of this point?
2007-03-01 14:07:54 · 6 answers · asked by chrischick2438 1 in Education & Reference ➔ Homework Help
This is probably easier to see if you have graph paper in front of you. First draw an x- and y-axis on the paper.
We know where the point ended up. Make a point at (-1,-1).
Now, we move back through the translation that got the point to this spot and we can find the original coordinates. Basically, we're going to travel BACK through the motion that got the point to this spot to find the original starting spot.
It was translated down 4 units, so we want to move UP 4 units.
It was translated left 6 units, so we want to move RIGHT 6 units.
We are now at the original position of the point. Count the horizontal distance from zero for the x-coordinate (t in this problem) and the vertical distance from zero for the y-coordinate (r in this problem) and you've found the original coordinates.
Good luck.
(The first four answers are all incorrect. OUCH!)
2007-03-01 14:18:31 · answer #1 · answered by infinityorzero 2 · 0⤊ 0⤋
+3, +5
2007-03-01 14:11:15 · answer #2 · answered by NHBaritone 7 · 0⤊ 1⤋
yeah, that dudes answer is right. what you do is add the first number with the first number, and the second with the second. In this instance, -1 + 4, for the first coordinate; and -1 + 6 for the second.
The solution is therefore ({-1+4=3},{-1+6=5}) or (3,5)
2007-03-01 14:14:55 · answer #3 · answered by Frankie D 1 · 1⤊ 1⤋
(5, 3)
2007-03-01 14:18:26 · answer #4 · answered by mostbeautifultruestoryevertold&l 3 · 1⤊ 0⤋
(5,4)? sry just did it in my head
2007-03-01 14:12:04 · answer #5 · answered by Kayla G 2 · 0⤊ 2⤋
Its (3,5)
2007-03-01 14:14:54 · answer #6 · answered by Myke Jones 1 · 0⤊ 1⤋