using substitution, you can first find x or y of one of the equations.
2x + 4y = 0
2x = -4y
x = -2y
then replace the x in the second equation with -2y.
2(-2y) + 6y = 6
-4y + 6y = 6
2y = 6
y = 3
and finally plug 3 in for y in either of the two equations to find x.
2x + 4(3) = 0
2x + 12 = 0
2x = -12
x = -6
the person above me made a small error.
2007-03-01 14:12:28
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answer #1
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answered by azncr0wn 2
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The best way to do this is using the addition method. If you are in algebra, you may be familar with this.Times everything on top by
-6 and the bottom by 4. it should turn out to be this:
-12-24y=0
8x+24y=24
then cancel out the additive inverses(24 and -24) and then add the rest. you should get an answer.
2007-03-01 22:08:11
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answer #2
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answered by oh 3
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2x+4y = 0
2x = -4y
x = -2y
2x + 6y = 6
2(-2y) + 6y = 6
-4y + 6y = 6
-2y = 6
y = -3
using x = -2y
x = -2 (-3)
x = 6
2007-03-01 22:12:25
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answer #3
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answered by rooster1981 4
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If you're trying to solve the system of the two equations, try solving each for y and graphing, then finding the intersection.
2007-03-01 22:01:00
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answer #4
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answered by Melanda 2
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In my math class, I learned that x=3 and y=2.2, so they are both false.
2007-03-01 22:02:22
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answer #5
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answered by Brian 3
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