Two bones of equal radius are subjected to equal twisting torques. If one is longer than the other which will fracture first?
2007-03-01 13:26:13 · 4 answers · asked by clars 1 in Health ➔ General Health Care ➔ Injuries
The longer one.
2007-03-01 13:35:17 · answer #1 · answered by Anonymous · 0⤊ 0⤋
If I remember my physics class correctly, the longer one will fracture first because torque is stronger with a bigger radius.
2007-03-01 21:34:27 · answer #2 · answered by Ayame 3 · 0⤊ 0⤋
also depends on the shape and the angle of the twisting. But in the twisting, which ever is the bigger of the two on the part that recieves the most stress would be the winner. And also, which ever has the better bone density....
2007-03-01 21:35:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
An educated guess. I say the longer one.
2007-03-01 22:21:26 · answer #4 · answered by ♨ Wisper ► 5 · 0⤊ 0⤋