35 grams of propane?
2007-03-01 13:05:45 · 4 answers · asked by shortydidi03 2 in Science & Mathematics ➔ Chemistry
about 57.28ml
2007-03-01 13:36:06 · answer #1 · answered by bige1236 4 · 0⤊ 0⤋
1. Write the BALANCED equation for the COMPLETE combustion of propane to give carbon dioxide and water.
2. Figure out stoichiometrically how many grams of water you will get via this balanced equation (1) from 35 grams propane.
Hint: Go from grams propane, to moles propane, to moles water to grams of water. If that is foreign or too hard to you, then you need serious tutorial attention. Get off of here and get some real live help.
3. Divide the grams by the given density, and you get volume of water in milliliiters.
2007-03-01 21:19:39 · answer #2 · answered by ? 4 · 0⤊ 0⤋
This is classic stoichiometry.
The balanced equation is
C3H8 + 5O2 == 3CO2 + 4H20
covert the 35 grams of propane to moles by dividing by the molecular mass.
Multiply by the molar ratio of 4/1, representing 4 moles of water per mole of propane.
Now multiply by 18 gr / mole for water and you have the grams and ml of water produced
2007-03-01 21:18:35 · answer #3 · answered by reb1240 7 · 0⤊ 0⤋
..2C3H8 + 10(O2) = 6CO2 + 8H2O
..H2O Mol.wt. = 2 + 16 = 18 :
..Moles:
..On the reactants side we have 2C3H8 = 80 mol. propane
..On the products side we have 8(H2O) = 8 x 18.
..= 144 mol. water.
..Moles can be expressed in any mass unit. We are using grams.
..We have 80g propane producing 144g water.
..1g propane will produce 144 ÷ 80 = 1.8g water
..35g propane will produce 1.8 x 35
..= 63g = 63ml water ... Answer.
(From this the moles of the other substances can be found)
2007-03-01 21:47:38 · answer #4 · answered by Norrie 7 · 0⤊ 0⤋