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The bar is at a 30 degree angle to the horizontal. Not taking into account air resistance what is the angular velocity of the bar after its center has dropped 10 feet.

2007-03-01 10:52:14 · 3 answers · asked by brcalaska 1 in Science & Mathematics Physics

The bar makes a 30 degree angle to the horizon. This bar IS 3 feet long, but it is not resting on anything or supported by anything. It is dropped with this initial angular velocity and I need to find what that angular velocity will be after it has fallen 10 feet.

2007-03-01 12:35:49 · update #1

The bar rotates about its center of mass, which is the midway point of the bar. Wouldn't the angular velocity not change if there is no wind resistance?

2007-03-01 12:38:15 · update #2

3 answers

Look, I have a big doubt with this, but isn't it 30 feet ??, because, how come can it dropeed 10 feet !!!, if it is onle 3 feet long, well, anyway, lets work with 30 feet.

Look, the angular velocity changes, because, the distance from the center of mass of the bar to the normal, you know, the vertical line es different when it drops. BUT IF THE BAR IS ROTATING AROUND ITS CENTER OF MASS, THEN THE ANGULAR VELOCITY WOULD NOT CHANGE, but I don't think that's the case in this problem, because the bar is making and angle with the horizon (30) degrees, I imagine, the bar, is rotating around one of it's ends.

The angular momentum (L) is the same at the beginning of the movement, and after it :

I*w = L = constant

I = m*r^2

where "r", is the distance from the center of the bar to the normal.

When it drops, the distance from the center of mass to the vertical will be :

r^2 = (5/2)^2 + (15/2)^2 = 62.5 = r^2

r = 7.9

20*[15*sqr(3)/4]^2*3 = 20*w*[sqr(62.5) ]^2

now, sqr(100), is the distance from the center of the bar to the normal

then :

3*20*42.18 = 20*62.5*w

w = 2.02 rad/s

Now, that will be the value of angular velocity after the bar drops 10 feet, if the bar is 30 feet long.

If you make a graphic of the problem, you will realize, the distances, and why it has to be 30 feet long

2007-03-01 11:19:57 · answer #1 · answered by anakin_louix 6 · 0 0

Is it held at one end?? The bar is 3 feet long. How can it drop 10 feet?? If it isn't held at one end, then Steve is right. Dropping something that is rotating won't affect the angular velocity??

2007-03-01 11:19:21 · answer #2 · answered by hello 6 · 0 0

I don't understand what axis the bar is rotating about or how dropping it could affect the angular velocity.......?????????

2007-03-01 11:02:28 · answer #3 · answered by Steve 7 · 0 0

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