the length of a string is 45 cm, if the period of the wave on the string is 1.2 x 10^-3 s. deduce that the speed of the wave is 250 m/s^2
2007-03-01 10:10:06 · 3 answers · asked by avemaria 2 in Science & Mathematics ➔ Physics
There's some information missing here. Since the string is capable of supporting a variety of harmonic modes, we need to know which mode it is to determine wave speed. The fundamental mode has a wavelength twice the length of the string. If that were the one you were seeing, the wave velocity would be 2L/p = 750 m/s. The wave you observed must then be the third harmonic, but you can't deduce the wave velocity without knowing that. (BTW, speed is m/s, not m/s^2).
2007-03-01 11:00:38 · answer #1 · answered by injanier 7 · 0⤊ 0⤋
Assuming the string is vibrating in its 'n' th mode of vibration then the string is vibrating in 'n ' segments with n+1 nodes and n anti nodes.
If ' l' is length of the string then wavelength will be 2l / n.
Now velocity of wave=wavelengthxfrequency
=wavelength / period
=2 l / (nT)=2x0.45 / n x 1.2 x 10^ - 3
=750 / n where n is 1 or 2 or 3 ......
therefore velocity can be 750 m/s or 375 m/s or 250m/s
2007-03-05 17:44:26 · answer #2 · answered by ukmudgal 6 · 0⤊ 0⤋
velocity = wavelength/period
v = .45m/(1.2*10^-3)s=375 m/s
2007-03-01 18:22:16 · answer #3 · answered by chris00780 2 · 0⤊ 0⤋