math homework plz help!!!!!!!!!!!!!!!!?

Question

At a movie theater, adult tickets cost $9.25 and children's tickets cost $5.50. One day a total of 126 tickets were sold. Total sales receipts equaled $903.00. How many of each type of ticket was sold?

Answer 1

9.25 x + 5.50y = 903
x + y = 126

Now you have a system of equations, so it should be fairly easy to solve for one variable and use that to get the other one. I chose to solve for y first, but you could just as easily do it the other way.

y = 126 - x
9.25 x + 5.50(126 - x) = 903

9.25x + 693 - 5.50x = 903
3.75x =210
x = 56

then plug the x = 56 into the second equation to get y

56 + y = 126
y = 70

Then you can check with the other equation, and you see that it all works out.

So, 56 adult tickets and 70 child tickets

Answer 2

9.25x + 5.50y = 903.00
x + y = 126

where x= # of adult's tickets
where y= # of children's tickets

x=126-y

substitute (126 - y) for x in the first equation and solve for y.


once you have a numerical value for y, plug that in the 2nd equation and solve for x.

x=56 and y=70

Answer 3

56 adult tickets
70 children tickets
x=adult
y=children
9.25x+5.50y=903.00
x+y=126
y=126-x
9.25x+5.50(126-x)=903.00
9.25x+693.00-5.50x=903.00
9.25x-5.50x=903.00-693.00
3.75x=210.00
(3.75x)/3.75 =(210.00)/3.75
x=56
56+y=126
y=126-56=70