calculate the freezing point of a 0.2 m CaCl2 aqueous solution, assuming it dissociates completely to form ion

Answer 1

ΔTf= i*Kf*m

for water Kf=1.858
for 100% dissociation you have 3 ions forming when the electrolyte dissociates according to its molecular formula (1 Ca+2 and 2 Cl- ions). Thus i=3

ΔTf = 3*1.858*0.2 = 1.11 deg C
but ΔTf = Tf0-Tf => Tf=Tf0 -ΔTf =0 -1.11= -1.11 deg C

Answer 2

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Answer 3

Latent Heat of Fusion = ?