How many ml of HCl would you need to dissolve in water to produce 1L of 1 M of HCl?

Question

Concentrated HCl is 18 molar. The molecular weight of HCl is 36.

Answer 1

We know that since the final concentration of HCL is 1M, and we have 1L of that, then the final solution has 1 mole of HCL.

The initial solution of concentrated HCL is 18M, and we want 1 mole of that, Just do:

1mole * (1L/18moles)= 1/18L, .056L, or 56mL of concentrated HCl. We then add water to that until we reach 1 L.

Answer 2

There are 18 mol HCl in 1L of 18 M HCl.

1000mL solution * (1 L / 1000 mL ) * ( 1 mol HCl / 1 L ) = 1.000 mol HCl
This tells us that you need 1 mol of HCl per L (duh).

You now need to use a volume of 18 M HCl that contains 1.000 mol HCl.
Volume * ( 18 mol HCl / L solution ) = 1.000 mol HCl
Solving for V gives...
1.000 mol HCl / 18.0 mol HCl = .056L or 55.6 mL of 18 M HCl.