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7 answers

pen 1 -- 5 pigs
pen 2 -- 3 pigs
put pen 3 inside pen 4 and put the pig in the middle. So there's one pig in both pens.

2007-03-01 06:49:55 · answer #1 · answered by Anonymous · 0 0

Pen # 1 - 5 Piggys
Pen # 2 - 1 Piggy
Pen # 3 - 3 Piggys
Pen # 4 - Around Pen # 3. :-D

2007-03-01 07:08:36 · answer #2 · answered by katlover118 2 · 0 0

its 30 pigs no longer 27 and you positioned them in 3 pens with an odd style of pigs in each and every pen nicely 30/3 =10 and 10/2 = 5 so which you have siz pens and you 2 pens in a million great pen so which you have 2 pens in each and every of the three pens and you positioned the divide the communities of five pigs in a million of the smaller pens and you have one pen with 10 pigs in each and every pen yet you have 2 little pens that incorporate the 5 pigs each and every so which you have 2 pens in a pen

2016-12-14 08:18:20 · answer #3 · answered by hume 4 · 0 0

Let's see...2 1/4 pigs for each pen. Hey, there's a loophole: u never said u can cut them up!

2007-03-02 08:00:43 · answer #4 · answered by mikezcim 5 · 0 0

Im rubbish at this. im not sure its possible.
what if you join two of the pens together to make one big pen. Then put 5 pigs in there. In the other 2 pens you put 1 pig and then 3 pigs. wrong i know. : (

2007-03-01 06:53:15 · answer #5 · answered by galaxy_callen 4 · 0 1

pens 1, 2, and 3 each have 3 pigs
the above 3 pens are enclosed in pen 4

why bother when you could have one big pig roast....sounds like a party to me!

2007-03-04 03:51:45 · answer #6 · answered by marlsk8s 1 · 0 0

kill the pigs and have pork chops for dinner

2007-03-01 06:53:51 · answer #7 · answered by angieward_2000 2 · 0 1

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