Calculate the change in free energy (KJ) for the reaction?

Question

Calculate the change in free energy (KJ) for the reaction


2H2S(g) + SO2(g) = 3S(s) + 2H2O(g)


under the following conditions:


T = 298 K
ΔGo = -90.0 kJ/mol



Pressure of H2S = 2.22 x 10-3 atm
Pressure of SO2 = 1.02 x 10-1 atm



Pressure of H2O = 2.60 x 10-2 atm

does anyone know if we have to convert atm to kj/mol?

Answer 1

OK.. The equation you need will relate the actual DG (How the heck DO you make a delta here?) to DGo and to the actual concentrations (pressures) of the reactants, symbolized in many books as "Q".

So, DG = DGo + RTlnQ

Q has the same form as the equilibrium constant, K, but uses non-equilibrium concentrations.

Plug in the values and calculate DG.