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what is the ph of a 0.03224 M solution of chloroacetic acid, for which Ka =1.36*10-3?

2007-03-01 04:58:45 · 1 answers · asked by jenrid 1 in Science & Mathematics ➔ Chemistry

1 answers

[H+] = root (Ka x 0.03224).

Then take the negative logaritm of [H+] to get the pH.

2007-03-01 05:28:46 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋

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