Determine the mass of weight 2. answer in KG?

Question

a left hand cable has a tention (T1) and makes an angle of 52 degrees with the horizontal. the right hand cable has a tention (T3) and makes an angle of 43 degrees with the horizontal. A weight (W1) is on the left and a weight (W2) is on the right. The cable connecting the two weights has a tenstion of 67N and is horizontal. acceleration of gravity is 9.8 m/s/s.

Answer 1

First, identify all the forces acting on the static system.

W1 = M1 g and W2 = M2 g. W1 is not moving; so it is counteracted by equal and opposite forces. Same for W2.

For W1, W1 = F1 = T1 sin(52). And for W2, W2 = T2 sin(43). These are the vertical forces of the system.

For the horizontal forces, we have 67 N = T1 cos(52) and 67 N = T2 cos(43) because the weights are not moving sideways; so the cable tensions in the horizontal directions are offset by the 67 N tension between the weights. Thus, T2 = 67/cos(43)

From these givens, we can see that W2 = T2 sin(43) = 67 (sin(43)/cos(43)) = 67 tan(43). From W2 = M2 g, we get M2 = W2/g = 67 tan(43)/9.81...you can do the math.