(5x+2)^2 + (4x-7)^2
2007-03-01 01:50:36 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(5x + 2)^2 + (4x - 7)^2
25x^2 + 4 + 20x + 16x^2 + 49 - 56x
41x^2 - 36x + 53
2007-03-01 01:57:29 · answer #1 · answered by Anonymous · 0⤊ 0⤋
(5x + 2)(5x + 2) = 25x² + 10x + 10x + 4 = 25x² + 20x + 4
(4x - 7)(4x- 7) = 16x² - 28x - 28x + 49 = 16x² - 56x + 49
- - - - - - - -
25x² + 20x + 4 + 16x² - 56x + 49 =
41x² - 36x + 53
- - - - - - -s-
2007-03-01 02:17:22 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
25x^2 + 20x + 4 + 16x^2 - 56x + 49
41x^2 - 36x + 53
2007-03-01 01:54:40 · answer #3 · answered by Doctor Q 6 · 0⤊ 0⤋
25x^2 +20x +4 + 16x^2 -56x + 49
41x^2 - 36x + 53
2007-03-01 02:00:21 · answer #4 · answered by Ray 5 · 0⤊ 0⤋
(A + B)^2 = A^2 + B^2+ 2AB
(A-B)^2= A^2+B^2-2AB
-> (5X+2)^2= 25X^2+4+20X ---(1)
->(4X-7)^2= 16X^2+49-56X---(2)
(1)+(2) =41X^2+53-36X
2007-03-01 01:57:28 · answer #5 · answered by Jaaji 2 · 0⤊ 0⤋
(5x+2)^2 + (4x-7)^2
= (25x² + 20x + 4) + (16x² - 56x + 49)
= (41x² - 36x + 53)
HTH ;)
2007-03-01 01:53:58 · answer #6 · answered by MamaMia © 7 · 1⤊ 0⤋
25x^2+20x+4+16x^2-56x+49
41x^2-36x+53
2007-03-01 02:06:48 · answer #7 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋